将0.2mol/L的醋酸(Ka=1.8×10-5)与0.2mol/L醋酸钠溶液混合,为使溶液的pH值维持在4.05,则酸和盐的比例应为( )。A. 6:1...

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问题 将0.2mol/L的醋酸(Ka=1.8×10-5)与0.2mol/L醋酸钠溶液混合,为使溶液的pH值维持在4.05,则酸和盐的比例应为( )。
选项 A. 6:1 B. 4:1 C. 5:1 D. 10:1
答案 C
解析

相关内容:0.2mol,醋酸,酸钠,溶液,混合,比例

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