频率4Hz沿x轴正向传播的简谐波,波线上有两点a和b若它们开始振动的时间差为0.25s,则它们的相位差为( )。A.π/2 B. π C. 3π/2 ...

作者: tihaiku 人气: - 评论: 0
问题 频率4Hz沿x轴正向传播的简谐波,波线上有两点a和b若它们开始振动的时间差为0.25s,则它们的相位差为( )。
选项 A.π/2 B. π C. 3π/2 D. 2π
答案 D
解析

相关内容:频率,传播,谐波,波线,振动,时间差,相位差

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