已知临街矩形地块甲的总价为36万元,临街宽度为20ft,临街深度为75ft。现有一相邻矩形地块乙,临街宽度为30ft,临街深度为125ft。运用“四三二一...

作者: rantiku 人气: - 评论: 0
问题 已知临街矩形地块甲的总价为36万元,临街宽度为20ft,临街深度为75ft。现有一相邻矩形地块乙,临街宽度为30ft,临街深度为125ft。运用“四三二一”法则,地块乙的总地价为()万元。
选项 A:65.4 B:81.8 C:87.2 D:109.0
答案 A
解析 设标准临街宗地总价为χ万元,则有36=x(40%+30%+20%),解得x=40万元。临街宽度为20ft,临街深度为125ft的地块的总价=40万元*(40%+30%+20%+10%+9%)=43.6万元,乙地块的总价=43.6万元/20*30=65.4万元。前街路线价
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