过点(-1,0,1)且与平面x+y+4z+19=0平行的平面方程为( )。A. x+y + 4z-3 = 0 B. 2x + y+z-3 = 0 C....

作者: tihaiku 人气: - 评论: 0
问题 过点(-1,0,1)且与平面x+y+4z+19=0平行的平面方程为( )。
选项 A. x+y + 4z-3 = 0 B. 2x + y+z-3 = 0 C. x+2y+z-19=0 D. x+2y+4z-9=0
答案 A
解析 正确答案是A。 提示:已知平面的法向量为n={1,1,4},由条件可取所求平面的法向量为n= {1,1,4}, 所以所求平面方程为:1x(x+1)+1x(y-0)+4x(z-1) = 0即x+y+4z-3= 0。

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