图4-42所示机构由杆O1A、O2B和三角板ABC组成。已知:杆O1A转动的角速度为ω,O1A=O2B=r, AC = h, O1O2 = AB,则图示瞬...

作者: tihaiku 人气: - 评论: 0
问题 图4-42所示机构由杆O1A、O2B和三角板ABC组成。已知:杆O1A转动的角速度为ω,O1A=O2B=r, AC = h, O1O2 = AB,则图示瞬时点C速度vc的大小和方向为( )。
选项 A. vc = rω,方向水平向左 B. vc = rω,方向水平向右 C. vc = (r+h)ω方向水平向左 D. vc= (r + h)ω,方向水平向右点
答案 A
解析 提示:三角形ABC作平行移动。

相关内容:机构,三角板,角速度

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